64.0k views
5 votes
Write an equation for a line perpendicular to y= -5x-1 and passing through the point of (10,3)

User Tom Teman
by
7.8k points

1 Answer

5 votes

Answer: The slope of a line perpendicular to y = -5x - 1 is 5, as the slopes are negative reciprocals of each other. To find the equation of a line passing through the point (10, 3), we can use the point-slope form of a line, which is:

y - y1 = m(x - x1)

where (x1, y1) is the point the line passes through, m is the slope of the line, and y and x are the variables representing the coordinates of a point on the line.

Plugging in the given values:

y - 3 = 5(x - 10)

Simplifying, we get:

y = 5x - 25 + 3

y = 5x - 22

So the equation of the line is y = 5x - 22

Explanation:

User Erik Fubel
by
8.0k points