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Draw the graph of y=f(x) and y= 1/f(x) on the same axes.

f) f(x) = -(x+4)²+1

are there any specific steps to get the answers here?

User Amitabha
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1 Answer

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Answer: To graph y = f(x) and y = 1/f(x) on the same axes, you can follow these steps:

First, graph y = f(x) by plotting a few points, such as (-5, -19), (-3, -1), (0, 1) and (5, 19), and then connecting them with a smooth curve.

Then, graph y = 1/f(x) by finding the inverse function of f(x) which will be

1/f(x) = -1/(x+4)²+1

Next, plot a few points on this new function, such as (-5, -1/19), (-3, -1), (0, 1) and (5, 1/19), and then connecting them with a smooth curve.

Finally, make sure that the same x and y scales are used for both graphs, and label the axes and the functions clearly.

It is important to note that as f(x) = -(x+4)²+1, the domain of f(x) is all real numbers but the range is (1, infinity) so the reciprocal will be defined only for the range of f(x) and the domain of 1/f(x) will be (1, infinity)

Also, the graph of y = f(x) will be a parabola opening upwards and y = 1/f(x) will be a parabola opening downwards, both with vertex (-4,1)

The graph of y = -(x+4)²+1 will be a parabola opening upwards and the graph of y = -1/(x+4)²+1 will be a parabola opening downwards.

Explanation:

User Iliya Reyzis
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