Answer: Let's call the first number "x" and the second number "y".
From the problem statement, we know that:
x = 3y - 6 (because one number is six less than three times the other number)
x + y = 38 (because the sum of the numbers is 38)
We can substitute the first equation into the second equation to solve for one of the variables:
3y - 6 + y = 38
4y - 6 = 38
4y = 44
y = 11
Now we can substitute this value of y back into the first equation to find the value of x:
x = 3(11) - 6
x = 29
So the two numbers are:
x = 29
y = 11
Explanation: