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One number is six less than three times another number. If the sum of the numbers is 38, find the numbers.

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Answer: Let's call the first number "x" and the second number "y".

From the problem statement, we know that:

x = 3y - 6 (because one number is six less than three times the other number)

x + y = 38 (because the sum of the numbers is 38)

We can substitute the first equation into the second equation to solve for one of the variables:

3y - 6 + y = 38

4y - 6 = 38

4y = 44

y = 11

Now we can substitute this value of y back into the first equation to find the value of x:

x = 3(11) - 6

x = 29

So the two numbers are:

x = 29

y = 11

Explanation:

User Herb Sutter
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