Check the picture below.
so the rectangle's perimeter is pretty much just 4 + 6 + 6 = 16, now let's notice the semi-circle, is really just half of a circle whose diameter is 4, meaning that its radius is 2, so let's simply get the circumference of that semi-circle and add it to 16.
![\textit{circumference of a semi-circle}\\\\ C=\cfrac{1}{2}\cdot 2\pi r \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=2 \end{cases}\implies C=\cfrac{1}{2}\cdot 2\pi (2)\implies C=2\pi \\\\[-0.35em] ~\dotfill\\\\ \stackrel{Perimeter}{16~~ + ~~2\pi} ~~ \approx ~~ \text{\LARGE 22.3}](https://img.qammunity.org/2024/formulas/mathematics/high-school/95vbm85oifpqk1iksel0303efi7wjf8jya.png)