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Solve the equation:(x+5)^4 = 81

2 Answers

2 votes

Answer:4√81=±3

Explanation:

User Arcanefoam
by
8.4k points
2 votes

If (x+5)^4 = 81,

then (x+5)^2 = ± sqrt(81), so

(x+5)^2 = ±9

Focusing on (x+5)^2 = 9 for the two real roots, we have

(x+5)^2 = 9

x+5 = ± sqrt(9)

x+5 = ± 3

x+5 = 3 gives you x = -2

x+5 = -3 gives you x = -8

There are two complex roots too, but I'm not sure if you're studying that too. If so, then you'd solve (x+5)^2 = -9:

x+5 = ± sqrt(-9)

x+5 = ±3i

x = 5 ± 3i as the two complex roots.

User Simeon Schaub
by
8.7k points

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