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3x + 2 > 2x - 3 > x - 12 solve the compound inequality

1 Answer

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Answer:

We get that x > -5

Explanation:

1. Split up the inequality into two parts

We think of it as a > b > c and know that it is the same as a > b and b > c.

Apply this to the compound inequality

3x + 2 > 2x-3 and 2x - 3 > x - 12

2. Start solving 3x + 2 > 2x-3

Subtract 2x from both sides

x + 2 >-3

Subtract 2 from both sides

x > -5

3. Start solving 2x - 3 > x - 12

Subtract x from both sides

x - 3 > -12

Add 3 to both sides

x > -9

4. Finish

Now we have to think how we started with 3x + 2 > 2x-3 and 2x - 3 > x - 12

Since it is an and we need to identify the interval in which it is true on both inequalities which is when the x overlap. In this case is from x > -5.

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