Question

Solve by substitution.
x - 2y = 3
2x + 4y = 6
([?], [ ]
Enter

Answer 1

`\begin{cases} x-2y=3\\ 2x+4y=6 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using the 1st equation}}{x-2y=3}\implies x=2y+3 \\\\\\ \stackrel{\textit{substituting on the 2nd equation}}{2(\underset{x}{2y+3})+4y=6}\implies 4y+6+4y=6\implies 8y+6=6 \\\\\\ 8y=0\implies y=\cfrac{0}{8}\implies \boxed{y=0}\hspace{5em}\stackrel{2(0)+3}{\boxed{x=3}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill (3~~,~~0)~\hfill`