Question

The length of the rectangle is seven times the width. The perimeter of the rectangle is 312 feet. Find the width and length of the rectangle.

Answer 1

The length is 273 and the width is 39

Explanation:

Given:

-The perimeter is 312 feet

-The length is seven times the width

Solution:

Let's say the width is x and the length is y.

So our equation is x + y = 312

But, 7x = y

If we substituted that into our equation, it would be:

7x + x = 312,

8x = 312

Divide by 8 on both sides,

x = 39

y = 273

So the length is 273 and the width is 39

Answer 2

This is a word problem that can be translated into an equation.
The perimeter of a rectangle is the sum of all four sides, so we can start with the formula:
Perimeter = 2(length) + 2(width)

We know that the perimeter is 312 feet, and we also know that the length is seven times the width, so we can substitute that into the equation:

312 = 2(7w) + 2(w)

Now we can solve for w (width).

312 = 14w + 2w
314 = 16w
w = 19.5

Now that we know the width, we can use the information that the length is seven times the width to find the length:

Length = 7 x Width = 7 x 19.5 = 137 feet

So, the width of the rectangle is 19.5 feet and the length of the rectangle is 137 feet