Answer:
We can find two other points on the line passing through (1,5) and (3,-1) by using the slope-intercept form of a line: y = mx + b where m is the slope of the line, and b is the y-intercept.
To find the slope (m) of the line, we can use the formula: m = (y2 - y1) / (x2 - x1)
Plugging in the coordinates of the two given points: m = (-1 - 5) / (3 - 1) = -6 / 2 = -3
To find the y-intercept (b) of the line, we can use one of the given points and substitute the values of x, y and m into the equation y = mx + b.
Plugging in the coordinates of the point (1,5) and the value of m: 5 = -3(1) + b, b = 8
So the equation of the line is y = -3x + 8
We can use this equation and any x value to find two other points on the line. For example, if we choose x = -2, we get y = -3(-2) + 8 = 2
so the point (-2,2) is on the line.
If we choose x = 0, we get y = -3(0) + 8 = 8
so the point (0,8) is on the line.
So two other points on the line passing through (1,5) and (3,-1) are (-2,2) and (0,8)
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