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A straight line passes through the points (3, k) and (-3, 2k). If the gradient of the line is -⅔. find the value of k. What is the equation of this line?​

User Vprasad
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Answer:

To find the value of k and the equation of the line, we can use the slope-intercept form of a line: y = mx + b, where m is the slope of the line, and b is the y-intercept.

The slope of the line (m) is given as -⅔. To find the y-intercept (b), we can substitute one of the given points and the value of m into the equation.

Let's use the point (3,k) :

y = mx + b

k = -⅔ * 3 + b

k = -2 + b

b = k + 2

Now we have the equation of the line in the slope-intercept form: y = -⅔x + (k + 2)

To find the value of k we can use the other point (-3, 2k) and substitute into the equation:

2k = -⅔(-3) + (k + 2)

2k = 2 + k + 2

k = -2

So the value of k is -2 and the equation of the line is y = -⅔x + (k + 2) = -⅔x - 2

This line is a straight line with the slope of -⅔ which passes through the points (3, k) and (-3, 2k) and its equation is y = -⅔x - 2

User Iaasgeek
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