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5x² + 10x + 2 in the form p(x +q)² + r,

1 Answer

2 votes

5(
x^(2) + 10/2
x) + 2

The number in the brackets is b/2a.

So:

5(x + 10/2(5))^2

5(x + 10/10)^2

5(x + 1)^2

Expand the double brackets for (x + 1)^2:


x^(2) +
x +
x + 1

This simplifies to:


x^2 + 2
x + 1

5(
x^2 + 2
x + 1)

5x^2 + 10x + 5

2 - 5 = -3

5(x + 1)^2 - 3

Answer:

5(x + 1)^2 - 3

User Kym
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