solution :
a²+3a-40
find the roots (2 numbers in which you can add and multiply to give 3a and 40)
(a-5) (a+8)
substitute the roots with 3a and multiply 40 by a²
a²-5a+8a-40a²
a(a-5) +8(a-40a²)
Answer:
(a + 8)(a - 5)
Explanation:
a² + 3a - 40 =
= (a )( )
Find two numbers that multiply to -40 and add to 3.
They are 8 and -5.
= (a + 8)(a - 5)
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