Question

A 1. 00 L volume of HCl reacted completely with 2. 00 L of 1. 50 M Ca(OH)2 according to the balanced chemical equation below. 2HCl Ca(OH)2 Right arrow. CaCl2 2H2O What was the molarity of the HCl solution? 0. 375 M 1. 50 M 3. 00 M 6. 00 M.

Answer 1

The first step is to find the number of moles of OH⁻ that reacted with the HCl. To do this multiply 2.00L by 1.50M to get 3 moles of Ca(OH)₂. Then you multiply 3 by 2 (there are 2 moles of OH⁻ per every 1 mole of Ca(OH)₂) to get 6 moles of OH⁻. That means that you needed 6 moles of HCl since 1 mole of HCl contains 1 mole of H⁺ and equal amounts H⁺ and OH⁻ reacted with each other. To find the molarity of the HCl solution you need to divide 6mol by 1L to get 6M. Tat means that the concentration of the acid was 6M.

I hope this helps. Let me know if anything was unclear.

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