Question

Consider the reaction shown.

4HCl(g)+O2(g)⟶2Cl2(g)+2H2O(g)

Calculate the number of grams of Cl2 formed when 0.460 mol HCl reacts with an excess of O2 .

Answer 1

16.4 g of Cl2

Step-by-step explanation:

4HCl(g) + O2(g) ⟶ 2Cl2(g) + 2H2O(g)

From the balanced equation, we know that for every 4 moles of HCl that react, 2 moles of Cl2 are formed. If we have 0.460 mol HCl, we can use the stoichiometry of the reaction to find the number of moles of Cl2 that will be formed.

0.460 mol HCl x (2 mol Cl2/4 mol HCl) = 0.230 mol Cl2

To find the number of grams of Cl2, we can use the molar mass of Cl2 (70.906 g/mol) and multiply it by the number of moles we just calculated.

0.230 mol Cl2 x 70.906 g/mol = 16.4 g Cl2

So, 0.460 mol HCl reacts with an excess of O2 to form 16.4 g of Cl2.