Answer:
11.1 moles of CO2
Step-by-step explanation:
2C2H6(g) + 7O2(g)⟶4CO2(g)+6H2O(g)
To find the number of moles of CO2 produced when 5.55 mol of ethane is burned in an excess of oxygen, use the stoichiometry of the reaction.
5.55 mol C2H6 x (4 mol CO2/2 mol C2H6) = 11.1 mol CO2
Therefore, 5.55 mol of ethane is burned in an excess of oxygen produces 11.1 moles of CO2.