Question

5. If 20kg body falls down ward freely from 40m building, find the kinetic energy of this body when at a height of 30m above the ground?​

Answer 1

300joules

Step-by-step explanation:

1÷2×20×30=

20×15=

Answer 2

The kinetic energy of an object is given as .5mv2, where m is

the mass of the object, and v is the velocity of the object. So in

this case, we can't determine the kinetic energy directly, but we

can determine the potential energy, which is given by mgh, where m

is the mass, g is the gravitaional constant, and h is the height

above the ground that the object falls from. We know that all of

the potential energy is going to be converted into kinetic energy.

So mgh = .5mv2. (20 kg)(9.8 m/s2)(30 m)= 5880J

Step-by-step explanation:

The kinetic energy of an object is given as .5mv2, where m is

the mass of the object, and v is the velocity of the object. So in

this case, we can't determine the kinetic energy directly, but we

can determine the potential energy, which is given by mgh, where m

is the mass, g is the gravitaional constant, and h is the height

above the ground that the object falls from. We know that all of

the potential energy is going to be converted into kinetic energy.

So mgh = .5mv2. (20 kg)(9.8 m/s2)(30 m)= 5880J