Question

Consider the reaction.

PCl5(g)↽−−⇀PCl3(g)+Cl2(g)=0.042

The concentrations of the products at equilibrium are [PCl3]=0.28 M and [Cl2]=0.10 M .

What is the concentration of the reactant, PCl5 , at equilibrium?

Answer 1

0.067 M

Step-by-step explanation:

The given equilibrium concentrations of the products are [PCl3]=0.28 M and [Cl2]=0.10 M.

Substitute these values into the expression for Kc to find the equilibrium concentration of the reactant, PCl5:

Kc = (0.28 M)(0.10 M) / [PCl5] = 0.042

Solving for [PCl5], you get:

[PCl5] = (0.28 M)(0.10 M) / 0.042 = 0.067 M

Therefore, the concentration of the reactant, PCl5, at equilibrium is 0.067 M.