Question

Draw rectangle HIJK, if HI = 3x + 7 and JK = 6x − 11,

find the value of x.

pls i need it​

Answer 1

x = 6

Explanation:

Vertices of a rectangle are normally listed so that adjacent vertices are connected by edges. Therefore, the edges of rectangle HIJK are HI, IJ, JK and KH.

As the opposite sides of a rectangle are congruent:

• HI = JK and IJ = KH

Therefore, to find the value of x, set the given expressions for HI and JK equal to each other and solve for x:

`\implies \sf HI=JK`

`\implies 3x+7=6x-11`

`\implies 3x+7-7=6x-11-7`

`\implies 3x=6x-18`

`\implies 3x-6x=6x-18-6x`

`\implies -3x=-18`

`\implies -3x / -3=-18 / -3`

`\implies x=6`