Hose 1 takes 7 days.
Hose 2 takes 4 days.
That means in a single day, Hose 1 fills 1/7 of the pool and Hose 2 fills 1/4 of the pool. So in one day, the two hoses will fill 1/7 + 1/4 of the pool.
If t is the number of days it takes to fill the pool with both hoses being used, then

will tell us how many days it will take to fill 1 pool
Solving this:
![\begin{aligned} t\cdot \left((1)/(7)\cdot(4)/(4) + (1)/(4)\cdot (7)/(7)\right) &=1 \\[0.5em]t\cdot \left((4)/(28) + (7)/(28)\right) &=1 \\[0.5em]t\cdot \left((11)/(28) \right) &=1 \\[0.5em]t &=(28)/(11) \\[0.5em]\end{aligned}](https://img.qammunity.org/2024/formulas/mathematics/college/11ddd1ljns21nrvs7xlyehn1682nkwgb3r.png)
It'll take 28/11 days, or 2 and 6/11 days, or about 2.54 days.