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Find the following areas under the normal curve

A. -1.43
B. 0.58
C. -1.55
D. z> 1.34

2 find the standardized score (z-score) closest to the following percentiles

A. 35th percentile

B. First Quartile QI

C. The observation with 12% of the data falling above it


3. Given a normal distribution of heights of 5 year olds (in inches) with a mean of 36 and a standard deviation of 10, find the following areas under the curve:

A. x< 31 inches

B. x> 49 inches

C. 40
D. 70% of 5 year olds are below what height?

1 Answer

3 votes

Answer:

1. A. -1.43 corresponds to an area of approximately 0.0637 under the normal curve.

B. 0.58 corresponds to an area of approximately 0.7295 under the normal curve.

C. -1.55 corresponds to an area of approximately 0.0633 under the normal curve.

D. For z>1.34, the area under the normal curve is approximately 0.0916.

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2. A. The 35th percentile corresponds to a z-score of approximately -0.48

B. The first quartile (Q1) corresponds to a z-score of approximately -0.67

C. For 12% of the data to fall above it, the z-score would be approximately 1.28

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3. A. To find the area under the curve for x< 31 inches, we need to convert 31 inches to a z-score using the formula: z = (x - mean) / standard deviation. For this case, z = (31 - 36) / 10 = -0.6, the area under the curve for this is 0.2744

B. To find the area under the curve for x> 49 inches, we need to convert 49 inches to a z-score, the z-score is (49 - 36) / 10 = 1.3, the area under the curve for this is 0.0968

C. The area under the curve for x = 40 inches is 0.3520

D. To find the height at which 70% of 5 year olds are below it, we need to use the inverse standard normal calculator, which gives us a z-score of 0.84162, we can then use this z-score to find the corresponding x value by using the formula x = mean + (z-score * standard deviation) which in this case would be 36 + (0.84162*10) = 42.4 inches

User Simon Kraemer
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