Answer:
To find the equation of the line passing through the point (3,2) and parallel to line x + 2y = 5, we need to use the point-slope form of a linear equation. The point-slope form of a linear equation is: y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.
We know that two lines are parallel if they have the same slope. Since the given line x + 2y = 5 has a slope of -1/2, the equation of the line passing through (3,2) and parallel to x + 2y = 5 is y - 2 = -1/2 (x - 3), or simplifying y = -1/2x + 7/2
To find the equation of the line passing through the point (2,5) and parallel to the line x + 3y - 8, we need to use the point-slope form of a linear equation. The point-slope form of a linear equation is: y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.
We know that two lines are parallel if they have the same slope. Since the given line x + 3y - 8 has a slope of 1/3, the equation of the line passing through (2,5) and parallel to x + 3y - 8 is y - 5 = 1/3 (x - 2), or simplifying y = 1/3x + 1/3
It's important to note that the lines are parallel because they have the same slope and different y-intercept, which means that they will never intersect.
Explanation: