Question

What is the mass, in grams, of 9.56 x 1024 molecules of methanol (CH3OH) ?

Answer 1

Step-by-step explanation:

Step (1) : find number of moles of (CH3OH)

`moles = \frac{number \: of \: molcule}{6.022 * {10}^(23) } \\ = \frac{9.56 * {10}^(24) }{6.022 * {10}^(23)} \\ = 15.8`

Step (2): find mass of (CH3OH)

`mass \: = moles * molecules \: mass \: of \:(CH3OH) \\ = 15.8 * 32.04 \\ = 506.2g`

Ao, answer is 506.2 g (approx 506g)