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2 votes
A sealed container can hold

0.325 L of gas at 1.00 atm
and 293 K. How many moles of gas
can the container hold?

1 Answer

3 votes

Answer:

0.0135 moles

Step-by-step explanation:

You want to know the number of moles of gas in a 0.325 L container at 1.00 atm and 293 K.

Moles

The ideal gas law is ...

PV = nRT

Solving for n, the number of moles can be found as ...

n = PV/(RT)

n = (101.325 kPa)(0.325 L)/(8.3145 L·kPa/(K·mol)·293 K) ≈ 0.0135 mol

The container can hold 0.0135 moles of gas.

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Additional comment

1.00 atm = 101.325 kPa

A sealed container can hold 0.325 L of gas at 1.00 atm and 293 K. How many moles of-example-1
User Carter Sande
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