To find the intermediate step in the form of (x+a)=b for the equation x^2+5x+11=13x, we need to first move all the terms to one side of the equation.
x^2+5x+11 = 13x
x^2 - 8x + 11 = 0
To solve this equation, we can factor it.
x^2 - 8x + 11 = 0
(x-11)(x-1) = 0
So, we have two solutions for x: x = 11 and x = 1
To find the intermediate step in the form of (x+a)=b, we can write each solution as (x+a)=b
x = 11, so (x+(-11)) = 11
x = 1, so (x+(-1)) = 1
So, the intermediate step in the form of (x+a)=b for the equation x^2+5x+11=13x is:
(x-11) = 11 and (x-1) = 1