Question

Solve each equation: Be sure to check the solutions:

1. X^2+17x+42=0
2. t^2-26t=56
3. y^2-84=5y
4. 17r+r^2=-52
PLEASE ANSWER QUICK!!!!!!!!!

Answer 1

1.

`{x}^(2) + 17x + 42 = 0 \\ using \: quadratic \: equation \: formula \\ x = \frac{ - 17± \sqrt{ {17}^(2) - 4 * 1 * 42 } }{2 * 1} \\ x = ( - 17±11)/(2) \\ for \: x = ( - 17 + 11)/(2) \\ x = - 3 \\ for \: x = ( - 17 - 11)/(2) \\ x = - 14`

Answer for 1 : x=-3, x=-14

2.

`t^2-26t=56 \\ also \: using \: quadratic \: equation \\ t = 28 \: or \: t = - 2`

Answer for 2: t=28, x=-2

3.

`y^2-84=5y \\ {y}^(2) - 5y - 84 = 0 \\ applying \: quadratic \: equation \\ y = 12 \: or \: y = - 7`

Answer for 3: y=12, y=-7

4.

`17r+r^2=-52 \\ {r}^(2) + 17r + 52 = 0 \\ r = - 4 \: or \: r = - 13`

Answer for 4: r=-4, r=-13

Answer 2

(1)... x1 = -14, x2 = -3

(2)... t1 = -2, t2 = 28

(3)... y1 = -7, y2 = 12

(4)... r1 = -13, r2 = -4

Explanation: