Question

A sealed container can hold 0.325 L of gas at 1.00 atm and 293 K. How many moles of gas can the container hold?

Answer 1

The sealed container can hold 4.499 moles of gas.

Step-by-step explanation:

To find the number of moles of gas that the container can hold, we can use the ideal gas equation, PV = nRT.

First, we need to convert the volume from liters to cubic meters, since the ideal gas constant (R) is given in SI units. Therefore, 0.325 L is equal to 0.000325 m^3.

Next, we can rearrange the equation and solve for the number of moles (n): n = PV / RT.

Substituting the given values into the equation, we have n = (1.00 atm * 0.000325 m^3) / (0.0821 atm * K^-1 * mol^-1 * 293 K).

Simplifying the expression, we get n = 4.499 moles (rounded to 3 decimal places).