Question

A sealed container can hold

6.28 L CO2 at 1.00 atm and 293 K.
How many moles of CO2 fill the
container?

Answer 1

0. 261

Step-by-step explanation:

Use ideal gas formula: PV = nRT, meaning that constant R =
`0.08206((L)(atm))/((K)(mol))`

`(1 atm)(6.28L) = n(0.08206((L)(atm))/((K)(mol)))(293 K) \\n = ((1 atm)(6.28L))/((0.08206((L)(atm))/((K)(mol)))(293 K)) \\n = 0.26119...\\n = 0.261`