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2 votes
An object is shot upwards, from the ground, with an initial velocity of 120

m/s. How high will it be after 4.0s?
480 m
402 m
380 m
302 m

User EricLaw
by
6.9k points

1 Answer

5 votes

We can use the kinematic equation: h = vit + 1/2g*t^2 to determine the height of an object shot upwards with an initial velocity of 120 m/s after 4.0s.

Where h is the height, vi is the initial velocity, t is the time, and g is the acceleration due to gravity (approximately 9.8 m/s^2).

h = 1204 + 1/29.8*4^2

h = 480m

The height of the object after 4.0s is 480m. So the answer is 480 m.

User Peter Van Kekem
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7.2k points