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2(3b+6) =78 : Answer is 11

-2(6c-3) = -72 : Answer is 6.5

Check Right and Left side of the equation

User Repincln
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The right side of the first equation is 78 and the right side of the second equation is -72. Both sides of the equations are constants (numbers with no variable in them)

The left side of the first equation is 2(3b+6) and the left side of the second equation is -2(6c-3). Both sides of the equations are products of a constant and a variable or a sum/difference of variables.

To find the value of b and c in the equation, you need to solve the equation.

For the first equation:

2(3b + 6) = 78

3b + 6 = 39

3b = 33

b = 11

For the second equation:

-2(6c - 3) = -72

6c - 3 = 36

6c = 39

c = 6.5

So, the value of b is 11 and the value of c is 6.5

User Cuzox
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