Question

Differentiate the given function.
y=x² √4x-3

Answer 1

`y=x^2√(4x-3)\implies \cfrac{dy}{dx}=\stackrel{\textit{\LARGE product rule}}{2x√(4x-3)~~ + ~~x^2\cdot \stackrel{\textit{chain rule}}{\cfrac{1}{2}(4x-3)^{-(1)/(2)}(4)}} \\\\\\ \cfrac{dy}{dx}=2x√(4x-3)~~ + ~~\cfrac{2x^2}{√(4x-3)}\implies \cfrac{dy}{dx}=\cfrac{8x^2-6x+2x^2}{√(4x-3)} \\\\\\ \cfrac{dy}{dx}=\cfrac{6x^2-6x}{√(4x-3)}\implies \cfrac{dy}{dx}=\cfrac{6x(x-6)}{√(4x-3)}`

Answer 2

Answer: I hope this helps you

Explanation: