Answer:
Coordinates of C are (22, 20)
Explanation:
We can see the squares are identical
The x-distance between A and B is 38 - 6 = 32
This covers 4 squares so each square side length = 32/4 = 8
Since point C is two squares away, the x-coordinate of C is 8 x 2 = 16 units away from the A x coordinate
x-coordinate of C = x-coordinate of A + 16 = 6 + 16 = 22
So x-coordinate of C is 22
To find the y-coordinate of C, because it is a square each vertical side of the square is also 8 units
If the third square were aligned with the top right of the second square, the y-coordinate of that square should be :
y-coordinate of A + 2 x 8 = 7 + 16 = 23
In this case, the y-coordinate of B should have been 23 + 2 x 8 = 23 + 16 = 39
However, because of the downward shift of the third square, the y-coordinate of B is only 36
39-36 = 3
So the third square has been shifted down by 3
Therefore y coordinate of C = 23 - 3 = 20
Coordinates of point C: (22, 20) which will result in the figure shown.
Just to verify
Since point B is 16 units to the right of C, its x-coordinate = 22 + 16 = 38
Point B
Point B y-coordinate is 16 units vertically up from y-coordinate of C.
So y-coordinate of B = 20 + 16 = 36
Hence verified
I hope that makes sense.
The attached figure shows exactly the figure in the question but with the coordinates marked. You can independently verify this