Answer:
- 30^(1/5) is in (1, 2)
- 45^(1/3) is in (3, 4)
Explanation:
You want to know the consecutive integers that bound the values of 30^(1/5) and 45^(1/3).
Powers and roots
The fifth root of 30 will lie between the two integers whose 5th powers lie on either side of 30:
1^5 = 1 < 30
2^5 = 32 > 30
So, the fifth root of 30 lies between 1 and 2:
![\boxed{1 < \sqrt[5]{30} < 2}](https://img.qammunity.org/2024/formulas/mathematics/high-school/lac25zh17j506er8vf806mqzq8f4gm32gu.png)
The cube root of 45 will lie between the two integers whose cubes lie on either side of 45:
3^3 = 27 < 45
4^3 = 64 > 45
So, the cube root of 45 lies between 3 and 4:
![\boxed{3 < \sqrt[3]{45} < 4}](https://img.qammunity.org/2024/formulas/mathematics/high-school/1dr0vidnzmy9achxm8q1ma8vdv2wiaxa6n.png)
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Additional comment
A calculator confirms this:
![\sqrt[5]{30}\approx 1.974\\\sqrt[3]{45}\approx3.557](https://img.qammunity.org/2024/formulas/mathematics/high-school/6anpcmto1omxsty4nz9h2d349v1wai3vc5.png)