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(a) Iff:R→R is defined by f(x) = x² +3, find the function g such that (fog)(x)=9x² -12x+7.​

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Explanation:

(f○g)(x) = f(g(x))

it simply means that we put the expression of g(x) into ask places of x in f(x).

(f○g)(x) = g(x)² + 3

therefore,

g(x)² + 3 = 9x² - 12x + 7

g(x)² = 9x² - 12x + 4 = (a + b)² = a² + 2ab + b²

9x² = a² tells us that a = ±3x

4 = b² tells us that b = ±2

which signs of a and b do we need ?

-12x = 2ab gives us the answer

-6x = ab

that means the signs need to be opposite and we have 2 possible solutions

g(x) = 3x - 2

or

g(x) = -3x + 2

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