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Find the area of triangle JKL below.
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Find the area of triangle JKL below.

Find the area of triangle JKL below.-example-1
User Fredrikekre
by
6.8k points

1 Answer

2 votes

Answer:

Explanation:

a/sin A=b/sin B

20/sin90⁰=x/sin60⁰

cross multiply

20sin60⁰=xsin90⁰

17.32=

area=1/2a/bsin∅

=1/2×17.32×20 sin30⁰

86.6square

User Jonathan Katon
by
7.4k points
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