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Find the area of triangle JKL below.

Find the area of triangle JKL below.-example-1

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Answer:

Explanation:

a/sin A=b/sin B

20/sin90⁰=x/sin60⁰

cross multiply

20sin60⁰=xsin90⁰

17.32=

area=1/2a/bsin∅

=1/2×17.32×20 sin30⁰

86.6square

User Jonathan Katon
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