Question

When Lavaughn moved into a new house, he planted two trees in his backyard. At the

time of planting, Tree A was 30 inches tall and Tree B was 15 inches tall. Each year
thereafter, Tree A grew by 2 inches per year and Tree B grew by 5 inches per year. Let
A represent the height of Tree At years after being planted and let B represent the
height of Tree B t years after being planted. Write an equation for each situation, in
terms of t, and determine which tree is taller after 6 years.
PLSSS HELPPPP

Answer 1

The height of Tree A t years after being planted can be represented by the equation:

A = 30 + 2t

This equation states that the initial height of the tree (30 inches) plus the annual growth of the tree (2 inches per year) multiplied by the number of years that have passed (t) will give the current height of the tree.

The height of Tree B t years after being planted can be represented by the equation:

B = 15 + 5t

This equation states that the initial height of the tree (15 inches) plus the annual growth of the tree (5 inches per year) multiplied by the number of years that have passed (t) will give the current height of the tree.

To determine which tree is taller after 6 years, we can substitute t = 6 into each equation and compare the results:

A = 30 + 2(6) = 30 + 12 = 42 inches

B = 15 + 5(6) = 15 + 30 = 45 inches

Tree B is taller than Tree A after 6 years because 45 inches is greater than 42 inches.

Answer 2

The starting point:

Tree A 30 inches
Tree B 15 inches

Equation:
Tree A: 30 + 2t

Tree B: 15 + 5t

Solving:

Since t represent time and you’re trying to figure out the growth after 6 years, plug 6 into t and solve.

Tree A: 30 + 2(6) = 42 inches

Tree B: 15 + 5(6)= 45 inches

Answer:
Tree B would be the tallest after 6 years.