Question

Re-write the quadratic function below in Standard Form
y=-2(x-3)(x+4)

Answer 1

`\boxed{-2x^2 -2x +24\\}\\\\`

Explanation:

The standard form of a quadratic function is:


`y = ax^2 + bx + c\\`

where a, b and c are constants

`\textrm{The given expression is $y=-2\left(x-3\right)\left(x+4\right)$}`

Expand the right side of this expression

`-2\left(x-3\right)\left(x+4\right)`

First expand (x-3)(x+4) using the FOIL method:

`(x-3)(x+4)`

`=x\cdot x+x\cdot \:4-3x-3\cdot \:4\\\\= x^2+x-12`

`-2\left(x-3\right)\left(x+4\right)\\\\= -2(x^2+x-12)\\\\= \boxed{-2x^2 -2x +24\\}\\\\`

ANSWER