Answer:
a=7300, b=1.0108.
L(t) = 7300(1.0108)^t
Explanation:
First, we can see that L(t) = 7300(1.012)^(4t) can be rewritten as L(t) = 7300e^(4tln(1.012))
Using the properties of logarithms, we can simplify this to L(t) = 7300e^(4t(ln(1.012))
Now, we can see that the function L(t) is in the form L(t) = ab^t, where a = 7300 and b = e^(ln(1.012))
Therefore, we can write the equivalent function as L(t) = 7300e^(0.048t)
The final values rounded to 4 decimal places are a=7300, b=1.0108.
L(t) = 7300(1.0108)^t