Hey there,
We have,
f(x) = x² + 11x + 30g(x) = x + 6
Now,
(f.g)(x) = f(g(x))
Substituting...
g(x) = x + 6f(g(x)) = f(x + 6)
f(x + 6)= (x + 6)² + 11(x + 6) + 30= x² + 12x + 36 + 11x + 66 + 30= x² + 23x + 132
So,The value is x² + 23x + 132
9.2m questions
11.9m answers