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How do you do the square root of 48 over the square root of 42 this is Algebra 1?

User Namek
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1 Answer

1 vote

Answer:

Explanation:

Simplify the following:

(sqrt(48))/(sqrt(42))

Rationalize the denominator. (sqrt(48))/(sqrt(42)) = (sqrt(48))/(sqrt(42))×(42^(1 - 1/2))/(42^(1 - 1/2)) = (sqrt(48)×42^(1 - 1/2))/42:

(sqrt(48)×42^(1 - 1/2))/42

Combine powers. (sqrt(48)×42^(1 - 1/2))/42 = sqrt(48)×42^((1 - 1/2) - 1):

sqrt(48)×42^((1 - 1/2) - 1)

Put 1 - 1/2 over the common denominator 2. 1 - 1/2 = 2/2 - 1/2:

sqrt(48)×42^((2/2 - 1/2) - 1)

2/2 - 1/2 = (2 - 1)/2:

sqrt(48)×42^(((2 - 1)/2) - 1)

2 - 1 = 1:

sqrt(48)×42^(1/2 - 1)

Put 1/2 - 1 over the common denominator 2. 1/2 - 1 = 1/2 - 2/2:

sqrt(48)×42^(1/2 - 2/2)

1/2 - 2/2 = (1 - 2)/2:

sqrt(48)×42^((1 - 2)/2)

1 - 2 = -1:

sqrt(48)×42^((-1)/2)

sqrt(48) = sqrt(2^4×3) = 2^2 sqrt(3):

2^2 sqrt(3) 1/sqrt(42)

2^2 = 4:

4 sqrt(3) 1/sqrt(42)

Rationalize the denominator. (4 sqrt(3))/(sqrt(42)) = (4 sqrt(3))/(sqrt(42))×(sqrt(42))/(sqrt(42)) = (4 sqrt(3) sqrt(42))/42:

(4 sqrt(3) sqrt(42))/42

The gcd of 4 and 42 is 2, so (4 sqrt(3) sqrt(42))/42 = ((2×2) sqrt(3) sqrt(42))/(2×21) = 2/2×(2 sqrt(3) sqrt(42))/21 = (2 sqrt(3) sqrt(42))/21:

(2 sqrt(3) sqrt(42))/21

sqrt(3) sqrt(42) = sqrt(3×42):

2/21 sqrt(3×42)

3×42 = 126:

(2 sqrt(126))/21

sqrt(126) = sqrt(3^2×14) = 3 sqrt(14):

2/21 3 sqrt(14)

3/21 = 3/(3×7) = 1/7:

Answer: (2 sqrt(14))/7

User Luxdvie
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