Question

Calculate Hydrogen reacts with excess nitrogen as follows: N2(g) + 3H2(g) → 2NH3(g)If 27.0 g of H2 reacts, what mass of NH3 is formed?

Answer 1

153 grams NH3

Step-by-step explanation:

The balanced equation

N2(g) + 3H2(g) → 2NH3(g)

tells us that 2 moles of ammonia are formed from every 3 moles of hydrogen. We can write this as

((2 moles NH3)/(3 moles H2))

If we convert the 27.0 grams of H2 to moles H2, we can use this factor to determine the moles NH3 that are formed.

Convert 27.0 grams H2 into moles H2 by dividing the moles by the molar mass of H2:

(27.0 grams H2)/(2 grams/mole H2)

13.5 moles H2

(13.5 moles H2)*((2 moles NH3)/(3 moles H2)) = 9 moles NH3

Now convert moles NH3 to grams NH2:

(9 moles NH3)(17 grams NH3/mole NH3) = 153 grams NH3