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Line q passes through the point 4,6 and 0,6 what is the equation for the line which is perpendicular to q and passes through the point -2,3

A x= -2
B x= -3
C y= -3
D y= -2

User IanPudney
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1 Answer

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The equation for line q is y = mx + b where m is the slope and b is the y-intercept. Since the line passes through the point (4,6) and (0,6), we can find the slope by using the formula m = (y2 - y1) / (x2 - x1) = (6 - 6) / (4 - 0) = 0.

Since the line is perpendicular to line q, the slope of the new line is the negative reciprocal of 0, which is undefined. Therefore, the new line is a vertical line, and the equation is in the form x = a constant. Since the line passes through the point (-2,3), the equation is x = -2. Therefore, the answer is A: x = -2.

User Ilya Tretyakov
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