Question

What will the following code print out? Can you write a similar method called tripleFirstFour() that triples the first 4 elements of the array? Make sure you test it in main.public class ArrayWorker{/** Doubles the first 5 elements of the array */public static void doubleFirstFive(int[] values){// Notice: && i < 5for (int i = 0; i < values.length && i < 5; i++){values[i] = values[i] * 2;}}/** Write a method called tripleFirstFour() that triples the first 4 elements of the array **/public static void printArray(int[] values){for (int i = 0; i < values.length; i++){System.out.println( values[i] );}}public static void main(String[] args){int[] numArray = {3, 8, -3, 2, 20, 5, 33, 1};doubleFirstFive(numArray);printArray(numArray);}}

Answer 1

The code will print out the elements of the array "numArray" after they have been doubled by the "doubleFirstFive" method. The "doubleFirstFive" method takes in an array as a parameter and uses a for loop to double the value of the first 5 elements of the array, using the "&& i < 5" condition in the for loop to ensure that only the first 5 elements are doubled.

A similar method called "tripleFirstFour" that triples the first 4 elements of the array can be written as follows:

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// Notice: && i < 4

for (int i = 0; i < values.length && i < 4; i++){

values[i] = values[i] * 3;

}

}

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To test the method, you can add the following code in the main method:

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tripleFirstFour(numArray);

printArray(numArray);

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This will call the "tripleFirstFour" method on the numArray and then print the new array out on the console.