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find the trapezoidal riemann sum approximation of the integral from 1 to 5 of the square root of quantity x squared plus 3 close quantity times dx using four equal partitions.

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6 votes

Answer:

14.115

Explanation:

Recall Trapezoidal Rule


\displaystyle \int\limits^b_a {f(x)} \, dx=(1)/(2)\biggr((b-a)/(n)\biggr)\biggr[f(x_0)+2\bigr(f(x_1)+f(x_2)+\text{... }+f(x_(n-1))\bigr)+f(x_n)\biggr]

Make necessary substitutions and evaluate


\displaystyle \int\limits^5_1 {√(x^2+3)} \, dx=(1)/(2)\biggr((5-1)/(4)\biggr)\biggr[2+2\bigr(√(7)+√(12)+√(19)\bigr)+√(28)\biggr]\approx14.115

Note that the actual value of the integral is
\displaystyle \int\limits^5_1 {√(x^2+3)} \, dx\approx14.078, so we can see how accurate the Trapezoidal rule is with just a few equal partions.

User Aksenov Vladimir
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