Answer:
H = 3
K = 0
Explanation:
To solve the system of linear equations using elimination by multiplication, we can first multiply the first equation by 3. This gives us:
3(H+2k)=3*3=9
3H+6k=9
Now we have the same coefficient (6k) on the second variable in both equations. We can now subtract the first equation from the second equation to eliminate the second variable:
3H+6k=9
-3H-6k=-9
0H=0
This tells us that the system of equations is consistent and has infinitely many solutions. To find the specific solution, we can use either equation and substitute in a value for one of the variables. For example, we can use the first equation and substitute in H=3. This gives:
3+2k=3
2k=0
k=0
Now we can substitute this value for k back into either equation to find the value of H. For example, using the first equation:
H + 2(0) = 3
H = 3
So the solution to the system of equations is:
H = 3, k = 0