Answer:
85,510 and 185.
Explanation:
let the first number be "a"
let the second number be "b"
let the third number be "c"
we know that
b=6a
c=100+a and
a+b+c=780
If we substitute the first 2 equations on the third one we get:
a+6a+100+a=780
8a+100=780
8a=780-100
8a=680
8 8
a=85
b=6a
b=6×85
b=510
c=100+a
c=100+85
c=185