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Water leaves a hose at a rate of 5.0 kg/s with a speed of 50 m/s. It strikes a wall which stops it (ignoring splash back). What is the force exerted by the water on the wall? Ans: -250 N

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Answer: Force = -250 N

Step-by-step explanation:

According to the question,

In 1 sec 5.0 kg water leaves the hose with a speed of 42 m/s

So initial momentum of 5.0kg water = 5.0 x 50 kg m/s

Since the water strikes the wall , it loses its speed to zero

Final momentum = 0

We know,

Force = Change in momentum / time

= (0 - 5 X 50) / 1

= -(5 X 50) / 1

= -250 N

Therefore the force exerted by the water leaving at a rate of 5.0 kg/s with a speed of 50 m/s on the wall is -250 N.

User Bryan Grace
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