Question

A rocket accelerates from rest at a rate of 66 m/s2. (a) What is its speed after it accelerates for 27 s?

Answer 1

We can use the equation:
v = u + at

Where:
v = final velocity
u = initial velocity (in this case, u = 0 since the rocket is starting at rest)
a = acceleration (66 m/s2)
t = time (27 s)

So substituting the given values, we get:
v = 0 + (66 m/s2)(27 s)
v = 1,782 m/s

Therefore, the rocket's speed after it accelerates for 27 s is 1,782 m/s