Answer:
C' U (A U B')
Explanation:
Using DeMorgan's laws
(C ∪ A' ∩ B)' = C' U (A' ∩ B)'
(A' ∩ B)' = (A')' U B' = A U B'
So (C ∪ A' ∩ B)' = C' U (A U B')
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