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Particles q1 = -66.3 UC, q2 = +108 uC, and

93 = -43.2 uC are in a line. Particles q1 and q2 are
separated by 0.550 m and particles q2 and q3 are
separated by 0.550 m. What is the net force on
particle q2?

User RobDil
by
7.4k points

1 Answer

3 votes

Final answer:

Where F is the force, k is the Coulomb's constant (9 * 10^9 Nm^2/C^2), q1 and q2 are the charges of the particles, and r is the distance between them. The net force on particle q2 is 2.75 Newtons. Hence, Therefore, the net force on particle q2 is 2.75 Newtons.

Step-by-step explanation:

The net force on particle q2 can be calculated using Coulomb's law.

Coulomb's law states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

The formula for Coulomb's law is:

F = k * |q1 * q2| / r^2

Where F is the force, k is the Coulomb's constant (9 * 10^9 Nm^2/C^2), q1 and q2 are the charges of the particles, and r is the distance between them.

In this case, q1 = -66.3 x 10^-6 C, q2 = +108 x 10^-6 C, and r = 0.550 m for both q1 and q2.

Plugging these values into the formula:

F = (9 * 10^9 Nm^2/C^2) * |-66.3 x 10^-6 C * 108 x 10^-6 C| / (0.550 m)^2

F = 2.75 N

Therefore, the net force on particle q2 is 2.75 Newtons.

User Pierre Baret
by
8.3k points