Answer:
- +3σ = $18,500
- -2σ = $16,000
- [-1σ, +1σ] = 68%
- [0,+2σ] = 47.5%
- (-∞, -2σ] = 2.5%
Explanation:
You want the percentages of buyers who paid prices in these intervals given the distribution of amounts paid is normal with mean $17000 and standard deviation $500:
- [$16500, $17500]
- [$17000, $18000]
- [$0, $16000]
And you want the prices that are 3σ above and 2σ below the mean.
Empirical rule
The prices in this question all differ from the mean by integer multiples of the standard deviation. This suggests that the answers are supposed to be found using the empirical rule, which tells us the fraction of the distribution within ±1σ of the mean is 68%, and within ±2σ is 95%.
A) 3σ Above
The price at µ+3σ is $17000 +3(500) = $18,500.
B) 2σ Below
The price at µ-2σ is $17000 -2($500) = $16,000.
C) $16500–$17500
These prices are µ±1σ, so the empirical rule tells us 68% of buyers paid in this range.
D) $17000–$18000
This is half the number that lie between -2σ and +2σ, so the empirical rule tells us 95%/2 = 47.5% of buyers paid in this range.
E) 0–$16000
This is half the number that lie outside of ±2σ, so the empirical rule tells us (1 -95%)/2 = 2.5% of buyers paid in this range.
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Additional comment
If you want more precise values, a probability calculator can provide them. The attached calculator display shows the percentages for C, D, E to be 68.3%, 47.7%, and 2.3%, respectively.
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